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Footnote callers should have a space after them (or before if the caller comes ahead of what it refers to, ESV-style). Is there a PT automatic check that will flag the case where the translator forgets to type that space?

पुराना पोस्ट - इसकी मूल भाषा में दिखाया जा रहा है
Paratext में द्वारा (1.4k अंक) | 807 व्यूज़

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सर्वोत्तम उत्तर

I don’t believe there is an automatic check built into Paratext. This is
the kind of thing i use Regular Expressions to look for. A simple check for
no space might look like:

regex:\\[fx]\*[^\s]

This should find as a regular expression any \f* or \x* followed by
something that is not a space.

anon848905
Americas Area Language Technology Coordinator
[Email Removed]
[Phone Removed]Office at JAARS)
[Phone Removed]Cell)
Skype name: anon848905

पुराना पोस्ट - इसकी मूल भाषा में दिखाया जा रहा है
द्वारा (9.9k अंक)
फिर से दिखाया गया

Did you mean:

regex:[fx]\*[^\s]

?

पुराना पोस्ट - इसकी मूल भाषा में दिखाया जा रहा है

No, I meant: (and in my sent items it show)

two backslashes before the [fx] and a backslash before the *

For some reason it got clobbered before it came out. This appears to be a problem with the way the Supporters site handles html. You actually have to double escape characters to get the to work correctly in the output. So what would need to be written in an email is:
regex:\\\\[fx]\\*[^\s]

anon848905
Americas Area Language Technology Coordinator
[Email Removed]
[Phone Removed]Office at JAARS)
[Phone Removed]Cell)
Skype name: anon848905

पुराना पोस्ट - इसकी मूल भाषा में दिखाया जा रहा है

This worked best for me:

regex:\\[fx]\*[^»“\)\]\}\-\s]

(where » and “ are the two types of close quotes we use in our language.)

The above finds callers that are definitely in the wrong place. Then I recheck the ones before close quotes, which may or may not be correct.

पुराना पोस्ट - इसकी मूल भाषा में दिखाया जा रहा है

@anon848905, if you put four spaces at the start of a line and a blank line before, it will be indented and formatted monospaced … plus, all backslashes are treated as literal backslashes, removing the need to double escape them.

पुराना पोस्ट - इसकी मूल भाषा में दिखाया जा रहा है

Oh, and this works nicely, particularly in RegEx Pal, to highlight the whole footnote, but not the punctuation or other character that follows:

\\f .*\\[fx]\*(?![\)\]\}»“\-\s])
पुराना पोस्ट - इसकी मूल भाषा में दिखाया जा रहा है

You might want to use this:

\\(f|x) .*?\\\1\*(?![\)\]\}»“\-\s])

\\(f|x) Look for footnotes or cross references
.*? “Non-greedy” (i.e. “match as little as possible”) for cases where there’s more than one footnote/cross ref per verse
\\ A backslash
\1 Either an f or an x
\*(?![\)\]\}»“\-\s]) Same as your expression

पुराना पोस्ट - इसकी मूल भाषा में दिखाया जा रहा है

Thanks. You added the professional touch!

पुराना पोस्ट - इसकी मूल भाषा में दिखाया जा रहा है
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If you found this topic interesting, then also see this thread.

पुराना पोस्ट - इसकी मूल भाषा में दिखाया जा रहा है
द्वारा (1.4k अंक)

संबंधित प्रश्न

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(Also see this thread.) Most publications that I read in English (including English Wikipedia) put footnote callers outside ... regex for it, I'll add it to this thread.
wdavidhj 1.4k पूछा गया जून 26, 2017
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1 उत्तर 236 व्यूज़
The character entered after the opening marker indicates what caller will be used in the text. In Unformatted view, you ... view, the character(s) you define will be displayed.
[Expert]
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2 उत्तर 533 व्यूज़
When I change the footnote callers to automatically-created callers, I get errors in the basic checks. I'm sure there is ... m missing somewhere, but I can't seem to find where!
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